Oh dear!
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Originally Posted by Dezmo
completely false....do you even understand what gyroscopic procession is? Simply put, any force applied to a spinning gyro will affect it 90 degrees in the direction of rotation....like when you try to turn the wheel sideways, but the bike leans over? make more sense now?
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Der, this is exactly what centrifugal force is. This a wheel spins around an axis and the force is 90 degrees to that axis ... not inwards or outwards but perpendicular to that axis.
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Its well doccumented that a bike rotates around its center of gravity when it leans into a turn, not around the contact patches. The bike leans right, the tire contact patch moves left. Nothing magical going on here, as the wheel is rolling as its path deviates and no loss of grip is needed.
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The tyre patch cannot move it is connected via grip to the road. The tyre does not move left the bike just leans right. Remember the CoG of the bike and rider combination have moved right also thanks to the lean.
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As to weight overcoming the gyro force....as I stated earlier, gravity doesnt overcome it, it works with it.
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I think you need to go and get a childs bicycle wheel and hold it by it's axle. Get somebody to spin it and try and see if this spinning of the wheel wants to make your hands move (thus simulate a bike wanting to lean) OR wants to make your hands move so the axle is horizontal.
It will make your hand move so the axle is horizontal and thus resist you wanting to move the axle or wheels axis around.
Correction: This is incorrect, please see next post of mine
Please note it is possible that we are trying to say similar things but thanks to terms and the written word we are miss-communicating ... it happens 
Pete